Integrand size = 15, antiderivative size = 251 \[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\frac {6}{5} c x^3 \sqrt {a+c x^4}+\frac {12 a \sqrt {c} x \sqrt {a+c x^4}}{5 \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\left (a+c x^4\right )^{3/2}}{x}-\frac {12 a^{5/4} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a+c x^4}}+\frac {6 a^{5/4} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{5 \sqrt {a+c x^4}} \]
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Time = 0.06 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {283, 285, 311, 226, 1210} \[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\frac {6 a^{5/4} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{5 \sqrt {a+c x^4}}-\frac {12 a^{5/4} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a+c x^4}}-\frac {\left (a+c x^4\right )^{3/2}}{x}+\frac {6}{5} c x^3 \sqrt {a+c x^4}+\frac {12 a \sqrt {c} x \sqrt {a+c x^4}}{5 \left (\sqrt {a}+\sqrt {c} x^2\right )} \]
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Rule 226
Rule 283
Rule 285
Rule 311
Rule 1210
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a+c x^4\right )^{3/2}}{x}+(6 c) \int x^2 \sqrt {a+c x^4} \, dx \\ & = \frac {6}{5} c x^3 \sqrt {a+c x^4}-\frac {\left (a+c x^4\right )^{3/2}}{x}+\frac {1}{5} (12 a c) \int \frac {x^2}{\sqrt {a+c x^4}} \, dx \\ & = \frac {6}{5} c x^3 \sqrt {a+c x^4}-\frac {\left (a+c x^4\right )^{3/2}}{x}+\frac {1}{5} \left (12 a^{3/2} \sqrt {c}\right ) \int \frac {1}{\sqrt {a+c x^4}} \, dx-\frac {1}{5} \left (12 a^{3/2} \sqrt {c}\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx \\ & = \frac {6}{5} c x^3 \sqrt {a+c x^4}+\frac {12 a \sqrt {c} x \sqrt {a+c x^4}}{5 \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\left (a+c x^4\right )^{3/2}}{x}-\frac {12 a^{5/4} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a+c x^4}}+\frac {6 a^{5/4} \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a+c x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 9.68 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.20 \[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=-\frac {a \sqrt {a+c x^4} \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},-\frac {1}{4},\frac {3}{4},-\frac {c x^4}{a}\right )}{x \sqrt {1+\frac {c x^4}{a}}} \]
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Result contains complex when optimal does not.
Time = 4.16 (sec) , antiderivative size = 122, normalized size of antiderivative = 0.49
method | result | size |
risch | \(-\frac {\sqrt {x^{4} c +a}\, \left (-x^{4} c +5 a \right )}{5 x}+\frac {12 i a^{\frac {3}{2}} \sqrt {c}\, \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )\right )}{5 \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {x^{4} c +a}}\) | \(122\) |
default | \(-\frac {a \sqrt {x^{4} c +a}}{x}+\frac {c \,x^{3} \sqrt {x^{4} c +a}}{5}+\frac {12 i a^{\frac {3}{2}} \sqrt {c}\, \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )\right )}{5 \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {x^{4} c +a}}\) | \(128\) |
elliptic | \(-\frac {a \sqrt {x^{4} c +a}}{x}+\frac {c \,x^{3} \sqrt {x^{4} c +a}}{5}+\frac {12 i a^{\frac {3}{2}} \sqrt {c}\, \sqrt {1-\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}, i\right )\right )}{5 \sqrt {\frac {i \sqrt {c}}{\sqrt {a}}}\, \sqrt {x^{4} c +a}}\) | \(128\) |
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\[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\int { \frac {{\left (c x^{4} + a\right )}^{\frac {3}{2}}}{x^{2}} \,d x } \]
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Result contains complex when optimal does not.
Time = 0.53 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.16 \[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\frac {a^{\frac {3}{2}} \Gamma \left (- \frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{2}, - \frac {1}{4} \\ \frac {3}{4} \end {matrix}\middle | {\frac {c x^{4} e^{i \pi }}{a}} \right )}}{4 x \Gamma \left (\frac {3}{4}\right )} \]
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\[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\int { \frac {{\left (c x^{4} + a\right )}^{\frac {3}{2}}}{x^{2}} \,d x } \]
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\[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\int { \frac {{\left (c x^{4} + a\right )}^{\frac {3}{2}}}{x^{2}} \,d x } \]
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Time = 5.97 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.16 \[ \int \frac {\left (a+c x^4\right )^{3/2}}{x^2} \, dx=\frac {{\left (c\,x^4+a\right )}^{3/2}\,{{}}_2{\mathrm {F}}_1\left (-\frac {3}{2},-\frac {5}{4};\ -\frac {1}{4};\ -\frac {a}{c\,x^4}\right )}{5\,x\,{\left (\frac {a}{c\,x^4}+1\right )}^{3/2}} \]
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